In projectile motion,the modulus of the rate | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In projectile motion,the only force acting on the projectile is gravity,which acts vertically downwards.According to Newton's second law of motion

Vedclass · Accepted Answer

constant

Vedclass · Answer

(A) In projectile motion,the only force acting on the projectile is gravity,which acts vertically downwards.According to Newton's second law of motion,the acceleration of the projectile is given by $\vec{a} = \frac{\vec{F}}{m} = \frac{m\vec{g}}{m} = \vec{g}$.The rate of change of velocity is defined as acceleration,i.e.,$\frac{d\vec{v}}{dt} = \vec{a} = \vec{g}$.The modulus of the rate of change of velocity is $|\frac{d\vec{v}}{dt}| = |\vec{g}| = g$.Since the acceleration due to gravity $g$ is constant throughout the motion,the modulus of the rate of change of velocity is also constant.

In projectile motion,the modulus of the rate of change of velocity is:

Similar Questions

$A$ body of mass $1 \, kg$ is projected from the ground at an angle of $30^{\circ}$ with the horizontal on level ground at a speed of $50 \, m/s$. The magnitude of the change in momentum of the body during its entire flight is ....... $kg \cdot m/s$ $(g = 10 \, m/s^2)$.

$A$ particle is projected from the ground with an initial speed of $v$ at an angle of projection $\theta$. The average velocity of the particle between its time of projection and the time it reaches the highest point of its trajectory is

$A$ body is projected at an angle $\theta$ so that its range is maximum. If $T$ is the time of flight, then the value of maximum range is (acceleration due to gravity $= g$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module